Product of Array Except Self
Given an array nums of n integers where n > 1, return an array output such that output[i] is equal to the product of all the elements of nums except nums[i]. Tags: Array
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Solution
class Solution:
def productExceptSelf(self, nums: List[int]) -> List[int]:
ans = [1 for i in range(len(nums))]
p = 1
for i in range(len(nums)):
ans[i] *= p
p *= nums[i]
p = 1
for i in range(len(nums) - 1, -1, -1):
ans[i] *= p
p *= nums[i]
return ans